0=x^2-2x+8

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Solution for 0=x^2-2x+8 equation: 



0=x^2-2x+8

We move all terms to the left:

0-(x^2-2x+8)=0

We add all the numbers together, and all the variables

-(x^2-2x+8)=0

We get rid of parentheses

-x^2+2x-8=0

We add all the numbers together, and all the variables

-1x^2+2x-8=0

a = -1; b = 2; c = -8;
Δ = b2-4ac
Δ = 22-4·(-1)·(-8)
Δ = -28
Delta is less than zero, so there is no solution for the equation

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